7th Standard Mathematics — Chapter 1
Exercise 1.5 Solutions
1. Temperature Change Problem
One night in Kashmir, the temperature is -5°C. Next day the temperature is 9°C. What is the increase in temperature?
Solution:
- Night temperature = -5°C
- Next day temperature = 9°C
- Increase in temperature = 9°C - (-5°C) = 9 + 5 = 14°C
Answer: The increase in temperature is 14°C.
2. Net Charge Determination
An atom can contain protons (+ charge) and electrons (- charge). Determine the net charge:
- 5 electrons and 3 protons → -5 + 3 = -2 (2 electrons)
- 6 Protons and 6 electrons → +6 + (-6) = 0 (Neutral)
- 9 protons and 12 electrons → +9 + (-12) = -3 (3 electrons)
- 4 protons and 8 electrons → +4 + (-8) = -4 (4 electrons)
- 7 protons and 6 electrons → +7 + (-6) = +1 (1 proton)
3. Celsius to Kelvin Conversion
Convert the following to Kelvin using the relation: K = T + 273
- -275°C: K = -275 + 273 = -2 K
- 45°C: K = 45 + 273 = 318 K
- -400°C: K = -400 + 273 = -127 K
- -273°C: K = -273 + 273 = 0 K
4. Bank Balance Problem
Find the amount left in the student's bank account (Initial balance = ₹ 690):
Transactions:
- Initial balance = ₹ 690
- (i) Deposit (+) = + ₹ 485 → Balance = 690 + 485 = ₹ 1175
- (ii) Withdrawal (-) = - ₹ 500 → Balance = 1175 - 500 = ₹ 675
- (iii) Withdrawal (-) = - ₹ 350 → Balance = 675 - 350 = ₹ 325
- (iv) Deposit (+) = + ₹ 89 → Balance = 325 + 89 = ₹ 414
Answer (iv): Balance after transactions = ₹ 414
(v) If another ₹ 300 was withdrawn, what would the balance be?
New Balance = 414 - 300 = ₹ 114
Answer (v): The final balance would be ₹ 114.
5. Poet Tamizh Nambi's Pages Problem
A poet Tamizh Nambi lost 35 pages of his 'lyrics' when his file got wet in the rain.
-
If Tamizh Nambi wrote 5 pages per day, how many days' work did he lose?
Total pages lost = 35
Days lost = 35 ÷ 5 = 7 days -
If 4 pages contained 1800 characters, how many characters were lost?
Characters in 1 page = 1800 ÷ 4 = 450 characters
Total characters lost = 35 × 450 = 15,750 characters -
If Tamizh Nambi is paid ₹250 for each page produced, how much money did he lose?
Money lost = 35 × ₹250 = ₹ 8,750 -
If Kavimaan helps Tamizh Nambi and they are able to produce 7 pages per day, how many days will it take to recreate the work lost?
Days required = 35 ÷ 7 = 5 days -
Tamizh Nambi pays Kavimaan ₹ 100 per page for his help. How much money does Kavimaan receive?
Money received by Kavimaan = 35 × ₹100 = ₹ 3,500
6. Riddle / Number Puzzle
Add 2 to me. Then multiply by 5 and subtract 10 and divide now by 4 and I will give you 15! Who am I?
Solution:
Let the number be x.
Step-by-step equation:
[ (x + 2) × 5 - 10 ] ÷ 4 = 15
(x + 2) × 5 - 10 = 15 × 4
(x + 2) × 5 - 10 = 60
(x + 2) × 5 = 70
x + 2 = 70 ÷ 5
x + 2 = 14
x = 14 - 2 = 12
Answer: The number is 12.
7. Profit and Loss Problem
Kamatchi, a fruit vendor sells 30 apples and 50 pomegranates. If she makes a profit of ₹ 8 per apple and loss ₹ 5 per pomegranate, what will be her overall profit or loss?
Solution:
- Profit from 30 apples = 30 × ₹ 8 = + ₹ 240
- Loss from 50 pomegranates = 50 × ₹ 5 = - ₹ 250
- Net Amount = +240 - 250 = - ₹ 10
Answer: She incurs an overall loss of ₹ 10.
8. Water Level Change Problem
During a drought, the water level in a dam fell 3 inches per week for 6 consecutive weeks. What was the change in the water level at the end of this period?
Solution:
- Water level change per week = -3 inches
- Total weeks = 6
- Total change = 6 × (-3) = -18 inches
Answer: The water level decreased by 18 inches (change of -18 inches).
9. Timeline / Historical Problem
Buddha was born in 563 BC(BCE) and died in 483 BC(BCE). Was he alive in 500 BC(BCE)? Find his lifetime.
Solution:
- Birth Year = -563
- Death Year = -483
1. Was he alive in 500 BC?
Since 500 BC (-500) falls between 563 BC (-563) and 483 BC (-483), Yes, he was alive in 500 BC.
2. Lifetime calculation:
Lifetime = Death Year - Birth Year = -483 - (-563) = -483 + 563 = 80 years.
Answer: Yes, he was alive in 500 BC. His total lifetime was 80 years.
No comments:
Post a Comment