7th Standard Mathematics — Chapter 3: Algebra
Exercise 3.2 Solutions
1. Fill in the blanks
- The addition of -7b and 2b is -5b.
- The subtraction of 5m from -3m is -8m.
- The additive inverse of -37xyz is 37xyz.
2. Say True or False
-
The expressions 8x + 3y and 7x + 2y can not be added.
Answer: FalseReason: They can be added by combining their like terms to get (8x + 7x) + (3y + 2y) = 15x + 5y. -
If x is a natural number, then x + 1 is its predecessor.
Answer: FalseReason: x + 1 is its successor, while x - 1 is its predecessor. -
Sum of a - b + c and -a + b - c is zero.
Answer: TrueReason: (a - a) + (-b + b) + (c - c) = 0 + 0 + 0 = 0.
3. Add
-
8x, 3x
8x + 3x = (8 + 3)x = 11x -
7mn, 5mn
7mn + 5mn = (7 + 5)mn = 12mn -
-9y, 11y, 2y
-9y + 11y + 2y = (-9 + 11 + 2)y = 4y
4. Subtract
-
4k from 12k
12k - 4k = 8k -
15q from 25q
25q - 15q = 10q -
7xyz from 17xyz
17xyz - 7xyz = 10xyz
5. Find the sum of the following expressions
-
7p + 6q, 5p - q, q + 16p
= (7p + 5p + 16p) + (6q - q + q)
= 28p + 6q -
a + 5b + 7c, 2a + 10b + 9c
= (a + 2a) + (5b + 10b) + (7c + 9c)
= 3a + 15b + 16c -
mn + t, 2mn - 2t, -3t + 3mn
= (mn + 2mn + 3mn) + (t - 2t - 3t)
= 6mn - 4t -
u + v, u - v, 2u + 5v, 2u - 5v
= (u + u + 2u + 2u) + (v - v + 5v - 5v)
= 6u + 0 = 6u -
5xyz - 3xy, 3zxy - 5yx
Note: xyz = zxy and xy = yx
= (5xyz + 3xyz) + (-3xy - 5xy)
= 8xyz - 8xy
6. Subtract
-
13x + 12y - 5 from 27x + 5y - 43
= (27x + 5y - 43) - (13x + 12y - 5)
= 27x + 5y - 43 - 13x - 12y + 5
= (27x - 13x) + (5y - 12y) + (-43 + 5)
= 14x - 7y - 38 -
3p + 5 from p - 2q + 7
= (p - 2q + 7) - (3p + 5)
= p - 2q + 7 - 3p - 5
= (p - 3p) - 2q + (7 - 5)
= -2p - 2q + 2 -
m + n from 3m - 7n
= (3m - 7n) - (m + n)
= 3m - 7n - m - n
= (3m - m) + (-7n - n)
= 2m - 8n -
2y + z from 6z - 5y
= (6z - 5y) - (2y + z)
= 6z - 5y - 2y - z
= (-5y - 2y) + (6z - z)
= -7y + 5z (or 5z - 7y)
7. Simplify
-
(x + y - z) + (3x - 5y + 7z) - (14x + 7y - 6z)
= x + y - z + 3x - 5y + 7z - 14x - 7y + 6z
= (x + 3x - 14x) + (y - 5y - 7y) + (-z + 7z + 6z)
= -10x - 11y + 12z -
p + p + 2 + p + 3 - p - 4 - p - 5 + p + 10
= (p + p + p - p - p + p) + (2 + 3 - 4 - 5 + 10)
= 2p + 6 -
n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
= n + m + 1 + n + 2 + m + 3 + n + 4 + m + 5
= (m + m + m) + (n + n + n) + (1 + 2 + 3 + 4 + 5)
= 3m + 3n + 15
No comments:
Post a Comment