Exercise 4.3

import os from weasyprint import HTML html_content = """

Chapter 4: Geometry

Exercise 4.3 Solutions

1. Observe the diagram and fill in the blanks.

Solution:

• (i) 'A', 'O' and 'B' are collinear points.
  Reason: They all lie on the same straight horizontal line.
• (ii) 'A', 'O' and 'C' are non-collinear points.
  Reason: They do not form a single straight line.
• (iii) 'A', 'B' and 'C' are non-collinear points.
  Reason: Point C lies outside the line passing through A and B.
• (iv) O is the point of concurrency.
  Reason: All three straight lines (AB, DC, and EF) intersect at the common point O.

2. Draw any line and mark any 3 points that are collinear.

Solution:

Collinear points are points that lie on the exact same straight line.

Points X, Y, and Z lie on the same line, making them collinear.

3. Draw any line and mark any 4 points that are not collinear.

Solution:

Non-collinear points do not all lie on a single straight line.

Points P, Q, R, and S are non-collinear because point S lies off the line.

4. Draw any 3 lines to have a point of concurrency.

Solution:

Concurrent lines are three or more lines that intersect at a single shared point.

Lines l₁, l₂, and l₃ intersect at the common point O. Point O is the point of concurrency.

5. Draw any 3 lines that are not concurrent. Find the number of points of intersection.

Solution:

When 3 lines are drawn such that they are not concurrent and no two lines are parallel, they form a triangle layout.

Conclusion: The number of unique points of intersection formed by these 3 non-concurrent lines is 3.

""" with open("exercise_4.3_solutions.html", "w") as f: f.write(html_content) HTML("exercise_4.3_solutions.html").write_pdf("exercise_4.3_solutions.pdf") print("PDF created successfully")